Well you can do this but it would be better if you did a fuel measurements to find out how much is actually needed for optimal performance.

To do this, you just have to do some fairly simple chemistry. The combustion of isopropyl alcohol id as follows:

2C3H8O + 9O2 -> 6CO2 + 8H2O

So the ratio of oxygen to isopropyl alcohol is 2:9 ratio. Then since 21% of air is oxygen we put that into the equation: 2/9 * .21 = .04666 or 4.7%. So 4.7% of the chamber volume should be the isopropyl alcohol.

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