What is a good ratio to follow as far as barrel to chamber size goes? Length wise and diameter wise. Thanks!
Ratios on my gun:
Length1:2
Width1:3
Any problems?
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RatiosWhat is a good ratio to follow as far as barrel to chamber size goes? Length wise and diameter wise. Thanks!
Ratios on my gun: Length1:2 Width1:3 Any problems?
These are useless, C:B ratios are always expressed as volume to volume. Diameter has very little effect in most cases.
Spudfiles' resident expert on all things that sail through the air at improbable speeds, trailing an incandescent wake of ionized air, dissociated polymers and metal oxides.
Here bro you need this. After you get your CB ratio off of this calc, you can ask this qustion
http://www.burntlatke.com/calc.html Ude the link above, once your there select and download RatClac. It will give you more presice CB ratios, and it will show you the correct way to right it.
Spudding Is dangerous, I learned the hard way:
http://www.spudfiles.com/forums/myeye ... 15301.html Guns. As They may Claim lives, they are lives. Our lives. When Life gives you lemons, through them at somone. Live, Breathe, Eat, Paintball
CannonCreator isn't that calculator for combustions not pneumatics?
I hear there is no perfect ratio in a pneumatic but there is a good guideline that it should be in, though I forogt what it is and can't find it.
Ratios for pneumatics depend on the pressure used. The higher the pressure, the larger the volume of the barrel should be for a given chamber size. At the pressures normally used, with a fixed chamber size, a .3:1 ratio can utilise most of the available power.
Spudfiles' resident expert on all things that sail through the air at improbable speeds, trailing an incandescent wake of ionized air, dissociated polymers and metal oxides.
DYI is a bit wrong since given the length to length ratio of the chamber and barrel, and the diameter ratios then volume ratios can be calculated. However, the normal way to express things is either as the volumes (or their ratio) or by giving the complete set of dimensions; length and width of both the chamber and barrel.
Of course, if you do it they way you did, you need to present the numbers in a manner that makes sense;
Does that mean the barrel is twice the length of the chamber and the diameter of the barrel is 3x the diameter of the chamber? Dosn't sound very likely. Did you mean;
from which the volume ratio can be calulated as; (volume chamber)/(volume barrel) = (pi)(r<sub>chamber</sub><sup>2</sup>)(L<sub>chamber</sub>) //(pi)(r<sub>barrel</sub><sup>2</sup>)(L<sub>barrel</sub>) canceling things gives; (r<sub>chamber</sub><sup>2</sup>)(L<sub>chamber</sub>) / (r<sub>barrel</sub><sup>2</sup>)(L<sub>barrel</sub>) Using the ratios in place of the actual r's and L's; (3<sup>2</sup>)(1)/(1<sup>2</sup>)(2) = 9/2 = 4.5 Now, like MrCrowley said, the optimal ratio of a pneumatic depends entirely on what you are trying to optimize. For optimal use of the available energy in the chamber then the barrel should be fairly long and the C:B fairly small, approaching roughly 1:9 (0.11 ratio) for a 120 PSIG chamber pressure. For optimal muzzle velocity for a fixed barrel length, the chamber should be as large as possible. The ratio might be 3:1 (3 ratio) or more.
 
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