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how do I calculate the tank to barrle ratio?I just orderd parts to make an over under air cannon. It is going to be a 3" air tank and a 2" barrle. I will have 5' lenghths of each. I want to know how to calculate the tank to barrle ratio so that i can decide how big im going to make it.
Last edited by cork9 on Fri May 04, 2007 8:35 pm, edited 1 time in total.
Chamber Volume divided by Barrel Volume should be in the range of 2:1 to 4:1 for optimal performance... Volumes are calculated using the following formula...
Volume = ((Inside Diameter / 2)^2 * 3.1416) * Length
barrel volume =754 ci
3:1 ratio = chamber volume of 251 ci length of 3 inch pipe needed= 9 inches long 4:1 ratio= chamber length of 188 inches length of 3 inch pipe needed=6.6 bottom line. you cant use the hole barrel *edit* those are B:C ratios (barrel comes first) ensted of C:B
Last edited by super spuder on Sat May 05, 2007 9:07 am, edited 2 times in total.
trying to decide on a new project, probably something small.
Sorry, i was under the impresion that C:B ratios were null and void on pneumatics....IMHO all the power comes from the flow/opening times of the valve
it does have some effect. 1017ci chamber
452 ci barrel =C:B ratio of 2.25:1 oh by the way. just ignore my previus post. i mesed up big time 1696 chamber (whole pipe) 753 barrel volume (whole pipe) = C:B ratio of 2.25:2 so just use both whole pipes by the way, sorry about the erlier post, i was tired
trying to decide on a new project, probably something small.
yea, i messed up, it was almose 11 so i was getting tired
trying to decide on a new project, probably something small.
 
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