stungun gun
- jackssmirkingrevenge
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Thank you for the JSR double entendre compendium hehe
hectmarr wrote:You have to make many weapons, because this field is long and short life
I think I missed a couple.jackssmirkingrevenge wrote:Thank you for the JSR double entendre compendium hehe
Seriously dude, with your efficiency and grammar Nazi-ing, your *facepalmheaddeskcombo*, the repeated innuendo and double entendre (so bad that the Flaming Pink Elephant was formed), inventing some extra double meaning, your foot aversions, internet memes and tendency for cannons that hang open and fart loudly - I'd say you're a teensy bit predictable.
In fact the only time you're not predictable is when someone accuses you of being predictable, and that in it's own way is predictable.
No doubt someone will now dissect me to show I'm hypocritical, so I'd like to start by saying I'm a hypocritical nerd with unnatural obsessions with wolves, safety, launchers, spelling and grammar, an unnatural hardiness, a tendency to use the word "Myriad", generally Bowdlerised (Except for the words "Bugger" and "bollocks"), a very typecast writing style, the habit of taking jokes and running off with them, a wannabe moderator, riding on the success of one particular cannon, a general eejit, occasionally mildly inspired, and probably too willing to see the best in people.
That's most of of it I think... no wait... and far too thorough when it's not important, forgot that one.
Does that thing kinda look like a big cat to you?
I put a multimeter across a photoflash cap, and the volts did tick off quite quickly... although I know they can still have enough charge to spark days after they were charged. Perhaps the rate drops off when they get to a lower V, or perhaps the loss of voltage was mainly from the multimeter.Ragnarok wrote:They can hold a charge for a good while longer than that. Can't tell you exactly how long, but they certainly don't lose charge that quickly.jimmy101 wrote:Off hand, I would WAG a photocap as losing perhaps one volt per second when fully charged to 300V.
I wonder how much deeper the ocean would be without sponges.
Right now I'm having amnesia and deja vu at the same time. I think I've forgotten this before.
Add me on msn!!! insomniac-55@hotmail.com
Right now I'm having amnesia and deja vu at the same time. I think I've forgotten this before.
Add me on msn!!! insomniac-55@hotmail.com
Yeah. Most multimeters have a resistance of about 1 megaohm across the wires in voltage mode, so you can't sit there with the multimeter constantly attached. You need to charge it, measure it once very quickly, then disconnect the multimeter and come back in a couple of minutes and measure it again, which generates much less voltage drop.Insomniac wrote:perhaps the loss of voltage was mainly from the multimeter.
Also true. The rate of discharge of a capacitor is directly proportional to the voltage in it. It will discharge twice as fast at 300V than 150V.Perhaps the rate drops off when they get to a lower V
This also technically means a capacitor can never truly fully discharge, because as it's voltage goes to zero, so does it's rate of discharge.
However, for practical purposes, we're talking mere millionths of volts.
Does that thing kinda look like a big cat to you?
Let me guess... You measured the resistance of your multimeter, with another multimeter.Ragnarok wrote:Most multimeters have a resistance of about 1 megaohm
I wonder how much deeper the ocean would be without sponges.
Right now I'm having amnesia and deja vu at the same time. I think I've forgotten this before.
Add me on msn!!! insomniac-55@hotmail.com
Right now I'm having amnesia and deja vu at the same time. I think I've forgotten this before.
Add me on msn!!! insomniac-55@hotmail.com
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- Corporal 5
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It's also usually written on it somewhere.
"If at first you dont succeed, then skydiving is not for you" - Darwin Awards
Voltmeters typically have a ohms/volt rating. So the input resistance will depend on the present voltage range setting.
So as an example, a typicial cheap analog meter may have a rating of 10,000 ohms/volt (or less). Therefore it's input resistance is going to be 500,000 ohms when it's set to the 50 VDC range and 100,000 ohms when its set at the 10 VDC range. Typically, the better the meter, the higher the ohms/volt rating is.
Digital meters almost always have a multiMEGohm range ohms/volt rating.
So as an example, a typicial cheap analog meter may have a rating of 10,000 ohms/volt (or less). Therefore it's input resistance is going to be 500,000 ohms when it's set to the 50 VDC range and 100,000 ohms when its set at the 10 VDC range. Typically, the better the meter, the higher the ohms/volt rating is.
Digital meters almost always have a multiMEGohm range ohms/volt rating.
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- Sergeant Major
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Wow, lots of folks know their meters! Analog meters have varying resitances depending on the voltage range. Usually it is printed on the dial face. Digital meters are much higher resistance and 10 Megaohm is common.
The rate at which a capacitor will disharge through a resistor is easy to calculate. About 63% of the cap's voltage will bleed off through the resistor in (resistance in ohms)(capacitance in farads) seconds. When the voltage cross a cap is measured with a meter the meter acts as the resistor.
A typical photo cap is 120 microfarad, figure 1 Megaohm resistance in the meter;
Time for cap's voltage to drop by ~63% = (120x10<sup>-6</sup> Farad)(1x10<sup>6</sup> Ohm) = 120 seconds
If the cap starts at 300V it will drop to 111 volts (a 63% drop from 300V) in 120 seconds. The initial voltage drop will be about 1.6 volts/second.
If the cap's leads are not connected to anything then the voltage will drop much more slowly. Perhaps a volt every few tens of seconds.
The rate at which a capacitor will disharge through a resistor is easy to calculate. About 63% of the cap's voltage will bleed off through the resistor in (resistance in ohms)(capacitance in farads) seconds. When the voltage cross a cap is measured with a meter the meter acts as the resistor.
A typical photo cap is 120 microfarad, figure 1 Megaohm resistance in the meter;
Time for cap's voltage to drop by ~63% = (120x10<sup>-6</sup> Farad)(1x10<sup>6</sup> Ohm) = 120 seconds
If the cap starts at 300V it will drop to 111 volts (a 63% drop from 300V) in 120 seconds. The initial voltage drop will be about 1.6 volts/second.
If the cap's leads are not connected to anything then the voltage will drop much more slowly. Perhaps a volt every few tens of seconds.
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its connected to a top and bottom rail note the color, so it will be connected until the capacitor exits the barreljimmy101 wrote:Not sure why you (in the OP) have the charging circuit at the muzzle (if I correctly understand the drawing). A high voltage high capacitance cap takes a while to fully charge. Photoflash boards take several seconds to charge their cap.
- jackssmirkingrevenge
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See I knew you'd say that ;pRagnarok wrote:No doubt someone will now dissect me to show I'm hypocritical
hectmarr wrote:You have to make many weapons, because this field is long and short life
And I knew you'd pick me up on saying it... :tongue5:jackssmirkingrevenge wrote:See I knew you'd say that ;p
And if I didn't say it, there were a great many people that I knew would say it instead.
You can't ever win in this game, you just keep going until someone flames you.
:violent3:
Does that thing kinda look like a big cat to you?
- jackssmirkingrevenge
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Thing is, when you don't live up to the image you've built up for yourself, folks tend to get a little disappointed and fear something might be amiss, it's a curse I tell you
hectmarr wrote:You have to make many weapons, because this field is long and short life