I know that you use 4.2% propane and the rest air. when you go to 2x do you use 8.4% and so on?
how much pressure of each would you use. there would be a difference in using .42 psi of propane and 9.58 psi of air and using 4.2 psi of propane and 95.8 psi of air. or would you use 14.7 psi for 1x and 29.4 for 2x and so on.
thanks
hybrid fueling
Firstly, you have no idea what you're doing, so I advise you do some research before you waste your money.
A 1x mix (regular combustion), in a completely airtight chamber, uses 14.7 psi air (atmospheric pressure), and about 0.644 psi propane. If the chamber isn't airtight (which is impossible for a hybrid), then it uses about 0.617psi of propane, because some air is displaced from the chamber.
You really should be able to figure it out from there if you're going to build a hybrid.
A 1x mix (regular combustion), in a completely airtight chamber, uses 14.7 psi air (atmospheric pressure), and about 0.644 psi propane. If the chamber isn't airtight (which is impossible for a hybrid), then it uses about 0.617psi of propane, because some air is displaced from the chamber.
You really should be able to figure it out from there if you're going to build a hybrid.
Spudfiles' resident expert on all things that sail through the air at improbable speeds, trailing an incandescent wake of ionized air, dissociated polymers and metal oxides.
Ok thanks,
so when I go to 2X I double the pressure of both right?
so when I go to 2X I double the pressure of both right?
Well, in the end its still 4.2% no matter what mixpat123 wrote:I know that you use 4.2% propane and the rest air. when you go to 2x do you use 8.4% and so on?
how much pressure of each would you use. there would be a difference in using .42 psi of propane and 9.58 psi of air and using 4.2 psi of propane and 95.8 psi of air. or would you use 14.7 psi for 1x and 29.4 for 2x and so on.
thanks
Just inject the normal amount of fuel (4.2%) twice, or more times and then pressurize it up further to your amount of mix with air.
If you inject one shot of propane for 4,2%, then inject air until there is atmospheric pressure inside, wich is probably in there already (unless you suck the chamber vacuum)
If you inject 2 shots of propane then inject air until you got 14,7psi (1 bar) in it.
If you inject 3 shots of propane then inject air until you got 2 bar in it.
And so on.
Chickens should not load your spud gun!
My original answer may not be right, as I'm not even sure that I understand the topic now - Spudblaster still has me confused, and I'm inclined to believe that he's right.
Spudfiles' resident expert on all things that sail through the air at improbable speeds, trailing an incandescent wake of ionized air, dissociated polymers and metal oxides.
so if I use one bar i use 4.2% of that and if I use 6 bar use 4.2% of that also right?
Take the total volume of gases in your chamber (converted to atmospheric pressure). Propane should comprise 4.2% of that. This is the end result that you want if you intend on it firing.so if I use one bar i use 4.2% of that and if I use 6 bar use 4.2% of that also right?
I suggest contacting SB15 for some rather mind-boggling advice on how to achieve this end result
Spudfiles' resident expert on all things that sail through the air at improbable speeds, trailing an incandescent wake of ionized air, dissociated polymers and metal oxides.